#include #include #include "DFT8Turbo.h" #include #include #define MAX_FREQS (8) #define OCTAVES (4) //Right now, we need 8*freqs*octaves bytes. //This is bad. //What can we do to fix it? //4x the hits (sin/cos and we need to do it once for each edge) //8x for selecting a higher octave. #define FREQREBASE 8.0 #define TARGFREQ 8000.0 /* Tradeoff guide: * We will optimize for RAM size here. * If you weight the bins in advance, you can: +) potentially use shallower bit depth but -) have to compute the multiply every time you update the bin. *TODO: Investigate using all unsigned (to make multiply and/or 12-bit storage easier) */ /* * The first thought was using an integration map and only operating when we need to, to pull the data out. * Now we're doing the thing below this block comment int16_t accumulated_total; //2 bytes int16_t last_accumulated_total_at_bin[MAX_FREQS*2]; //24 * 2 * sizeof(int16_t) = 96 bytes. uint8_t current_time; //1 byte uint8_t placecode[MAX_FREQS]; */ /* So, the idea here is we would keep a running total of the current ADC value, kept away in a int16_t. It is constantly summing, so we can take an integral of it. Or rather an integral range. Over time, we perform operations like adding or subtracting from a current place. */ //These live in RAM. int16_t running_integral; int16_t integral_at[MAX_FREQS*OCTAVES*2]; //THIS CAN BE COMPRESSED. int32_t cossindata[MAX_FREQS*OCTAVES*2]; //Contains COS and SIN data. (32-bit for now, will be 16-bit, potentially even 8.) uint8_t which_octave_for_op[MAX_FREQS]; //counts up, tells you which ocative you are operating on. PUT IN RAM. #define NR_OF_OPS (4< hits per %d: %f %d (%.2f%% error)\n", topbin, f, ACTIONTABLESIZE, (float)ACTIONTABLESIZE/f, dhrpertable, err * 100.0 ); if( dhrpertable >= ACTIONTABLESIZE ) { fprintf( stderr, "Error: Too many hits.\n" ); exit(0); } float advance_per_step = dhrpertable/(float)ACTIONTABLESIZE; float fvadv = 0.0; int j; int countset = 0; //XXX TODO Tricky: We need to start fadv off at such a place that there won't be a hicchup when going back around to 0. for( j = 0; j < ACTIONTABLESIZE; j++ ) { if( fvadv >= 0.5 ) { actiontable[j] |= 1<> longestzeroes) & 1) == 0 ); longestzeroes++ ); //longestzeroes goes: 255, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, ... //This isn't great, because we need to also know whether we are attacking the SIN side or the COS side, and if it's + or -. //We can actually decide that out. if( longestzeroes == 255 ) { //This is a nop. Emit a nop. optable[i] = 255; } else { longestzeroes = OCTAVES-1-longestzeroes; //Actually do octave 0 least often. int iop = phaseinop[longestzeroes]++; int toop = (longestzeroes<<1) | (iop & 1); //if it's the first time an octave happened this set, flag it. This may be used later in the process. if( !already_hit_octaveplace[toop] ) { already_hit_octaveplace[toop] = 1; toop |= 1<<5; } //Handle add/subtract bit. if( iop & 2 ) toop |= 1<<4; optable[i] = toop; //printf( " %d %d %d\n", iop, val, longestzeroes ); } //printf( "HBT: %d = %d\n", i, optable[i] ); } //exit(1); return 0; } #if 0 int16_t running_integral; int16_t integral_at[MAX_FREQS*OCTAVES]; int16_t cossindata[MAX_FREQS*OCTAVES*2]; //Contains COS and SIN data. uint8_t which_octave_for_op[MAX_FREQS]; //counts up, tells you which ocative you are operating on. PUT IN RAM. #define NR_OF_OPS (4<>2; #define dprintf( ... ) uint32_t action = actiontable[actiontableplace++]; int n; dprintf( "%4d ", actiontableplace ); for( n = 0; n < MAX_FREQS; n++ ) { if( action & (1<= NR_OF_OPS ) ao = 0; which_octave_for_op[n] = ao; if( op == 255 ) { dprintf( "*" ); //NOP } else { int octaveplace = op & 0xf; int idx = (octaveplace>>1) * MAX_FREQS * 2 + n * 2 + (octaveplace&1); //int invoct = OCTAVES-1-octaveplace; int16_t diff; if( op & 0x10 ) //ADD { diff = integral_at[idx] - running_integral; dprintf( "%c", 'a' + octaveplace ); } else //SUBTRACT { diff = running_integral - integral_at[idx]; dprintf( "%c", 'A' + octaveplace ); } if( diff > 256 || diff < -256 ) printf( "%d\n", diff ); integral_at[idx] = running_integral; //if( n == 1 ) printf( "%d %d %d %d\n", n, idx, diff, op & 0x10 ); //dprintf( "%d\n", idx ); #if 0 //Apply IIR operation 1; This is rough because the Q changes and goes higher as a function of frequency. This is probably a bad move. cossindata[idx] += diff>>4; if( op & 0x20 ) { cossindata[idx] = cossindata[idx] - (cossindata[idx]>>2); } #else //Apply IIR. //printf( "%d: %d + %d * %d >> 8 - %d\n", idx, cossindata[idx], diff, mulmux[idx/2], cossindata[idx]>>4 ); cossindata[idx] = cossindata[idx] + (((int32_t)diff * (int32_t)mulmux[idx/2])>>6) - (cossindata[idx]>>4) ; // if( cossindata[idx] > 2047 ) cossindata[idx] = 2047; // if( cossindata[idx] < -2048 ) cossindata[idx] = -2048; #endif // if( cossindata[idx] > 1 ) cossindata[idx]--; // if( cossindata[idx] < -1 ) cossindata[idx]++; // if( cossindata[idx] > 16 ) cossindata[idx]-=8; // if( cossindata[idx] < -16 ) cossindata[idx]+=8; } } else { dprintf( " " ); } } dprintf( "\n" ); #if 0 uint32_t actions = *(placeintable++); if( placeintable == &actiontable[ACTIONTABLESIZE] ) placeintable = actiontable; int b; for( b = 0; b < MAX_FREQS; b++ ) { if( ! ((1<>= 1; int octavebit = op & ((1<>5 ); //6 = Actually only feed algorithm numbers from -64 to 63. } last_place = place_in_data_buffer; static int idiv; idiv++; #if 1 for( i = 0; i < bins; i++ ) { outbins[i] = 0; } for( i = 0; i < bins; i++ ) { int iss = cossindata[i*2+0]>>8; int isc = cossindata[i*2+1]>>8; int issdiv = 0; int iscdiv = 0; int FWDOFFSET = 19;//MAX_FREQS*3/2; if( i < bins-FWDOFFSET ) { issdiv = cossindata[(i+FWDOFFSET)*2+0]/256; iscdiv = cossindata[(i+FWDOFFSET)*2+1]/256; } int mux = iss * iss + isc * isc; int muxdiv = issdiv * issdiv + iscdiv * iscdiv; //if( (idiv % 100) > 50 ) { printf( "*" ); mux -= muxdiv; } //mux -= muxdiv; if( mux <= 0 ) { outbins[i] = 0; } else { //if( i == 0 ) //printf( "MUX: %d %d = %d\n", isc, iss, mux ); outbins[i] = sqrt((float)mux)/50.0; if( abs( cossindata[i*2+0] ) > 1000 || abs( cossindata[i*2+1] ) > 1000 ) printf( "%d/%d/%d/%f ", i, cossindata[i*2+0], cossindata[i*2+1],outbins[i] ); //outbins[i] = (cossindata[i*2+0]/10000.0); } } printf( "\n" ); #endif }